![]() = bottom equilibrium stage for an absorption column = liquid flow rate on a solute-free basis (mol liquid absorbent time -1) = equilibrium constant, (mole fraction solute in gas)/(mole fraction solute in liquid) Watch a video from LearnChemE that demonstrates how to determine the number of equilibrium stages required for an absorption column when given inlet and outlet specifications: Absorption of a Dilute Species (10:43): ĭetermining the Minimum Ratio for Absorbent to Gas Flow Rates and a Mathematical Approach for Finding the Number of Equilibrium Stages ![]() = mole ratio of solute/gaseous carrier in gas entering the bottom of the absorption column = mole ratio of solute/gaseous carrier in gas leaving the top of the absorption column = mole ratio of solute in gas phase (mol solute/mol gaseous carrier) = mole fraction of solute in gas phase (mol solute/mol total gas) = mole ratio of solute/absorbent in liquid leaving the bottom of the absorption column = mole ratio of solute/absorbent in liquid entering the top of the absorption column = mole ratio of solute in liquid phase (mol solute/mol liquid absorbent) = mole fraction of solute in liquid phase (mol solute/mol total liquid) = gas flow rate on a solute-free basis (mol gaseous carrier time -1) For a stripping column, is the top stage. For an absorption column, is the bottom stage. = liquid flow rate on a solute-free basis (mol time -1) = equilibrium constant, (mole fraction in gas)/(mole fraction in liquid) (8.6) Graphical Method to Find Equilibrium Stages for Absorption Columns How many theoretical stages would be required for (L/V) = 1, (L/V) = 2, and (L/V) = 10? We intend to absorb 90% of the acetone entering in the gaseous phase into the liquid phase. K for acetone in an air/water system is 2.0.
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